6800 FCOE硬件zone资源不足计算方法

无

现场在激活zoneset的时候，报硬件资源不足：

%Feb 26 16:43:26:243 2020 NTZWY-SU8300-A SHELL/6/SHELL_CMD: -Line=aux0-IPAddr=**-User=**; Command is zoneset activate name ntszf

%Feb 26 16:43:27:967 2020 NTZWY-SU8300-A FCZONE/4/FCZONE_HARDZONE_DISABLED: -VSAN=100; No enough hardware resource for zone rule, switched to soft zoning.

这个不影响业务，默认是硬Zone，硬件ACL实现，超出后硬件规格后，切软Zone，对业务无影响，实现方式的变化。虽然对业务无影响，那么资源占有情况到底如何计算呢？

计算方法：

1.      硬zone规格这么看：

Debug fcoe show statistic

[NTZWY-SU8300-A-probe]debug fcoe show statistic slot 1

**********************************************************

Fcagg SPECS:

- Cur Num:               0

- Max Num:              128

- ShareMode:          LocalFirst

-----------------------------------

Current FCoE Mode:FCF.

-----------------------------------

ROUTE SPECS:

[Hard Info]

- Max Num:              256

- Reserved Num:              8

- Route Num:           49

[Soft Info]

- Refresh-flag:                  0

- Refresh-count:              0

- Route Num:           50

NEXTHOP SPECS:

- Hard Num:             29

- Soft Num:              29

VSAN SPECS:

- Max Num:              33

- Vsan Num:             3

ZONE/NPV SPECS:

[Hard Info]

- Max Num:              256-------这个是硬件zone规格

- Reserved  Num:             3

- ZONE Rule Num:           0

- NPV Mapping Num:      0

[Soft Info]

- ZONE Refresh-flag:      0

- ZONE Refresh-count:   2

- ZONE Rule Num:           1

- NPV Mapping Num:      0

FIPS SPECS:

[Hard Info]

- Max Num:              256

- Reserved Num:              4

- FIPS Num:              0

[Soft Info]

- Refresh-flag:                  0

- Refresh-count:              0

- FIPS Num:              0

**********************************************************

----------------------------------------------------------------------

  Pri  6, Group  4,usedEntries   57,mode Single, physlice 9/

  ==================================================================

    acl type             usedEntries[57]  all[256]  remain[199]

  ==================================================================

    [124]FCOE TO CPU Shadow          1  

    [125]FCOE TO CPU                 6  

    [126]FCOE ROUTE                  49 

    [131]FCOE CLASSSCIFY SYS         1  

  ==================================================================

----------------------------------------------------------------------

  Pri  7, Group  5,usedEntries    3,mode Single, physlice 8/

  ==================================================================

    acl type             usedEntries[3]  all[256]  remain[253]

  ==================================================================

    [128]FCOE FIPS DENY              2  

    [204]FCOE ZONE PERMIT            1  

  ==================================================================

2.      软zone无限制。

3.      计算方式：

一、            FCF模式：

查看acl硬件资源：

------------------------------------------------------

  Pri  7, Group  5,usedEntries  167,mode Single, physlice 8/

  =========================================

    acl type                   usedEntries[167]

  =========================================

    [127]FCOE FIPS DENY              2  

    [203]FCOE ZONE PERMIT            1  

    [126]FCOE ZONE                   164

  ======================================

------------------------------------------------------

1.       查看[68-4C-probe]debug qacl show acl-resc slot 2 chip 0，主要看总数超没超过256

acl type                   usedEntries[167]       —— 看超没超过256

2.       计算步骤1：此处为固定数量

    [127]FCOE FIPS DENY              2  

3.       计算步骤2：vsan绑定vlan，则加1

[203]FCOE ZONE PERMIT            1  

一个vsan绑定一个vlan，则加1

#

vlan 10

fcoe enable vsan 10

#

4.       计算步骤3

1)       看vsan下有几个zone，之间是相加的关系

2)       看zone里面几个member，按着A_mⁿ    的排列组合方式计算

3)       以如下两个zone的配置计算为例

zone name zhzjglrac2_V2E1D1F0

  member pwwn 21:00:00:21:5e:e2:f8:69

  member pwwn 50:00:14:42:b0:2f:58:00

zone name VMAX2_2E1_NEI_WANG_VM_GK

  member pwwn 10:00:00:00:c9:95:d1:bf

  member pwwn 10:00:00:90:fa:96:d8:09

  member pwwn 10:00:00:90:fa:96:d9:81

  member pwwn 10:00:02:00:c9:90:85:fb

  member pwwn 10:00:2c:76:8a:82:24:a9

  member pwwn 10:00:2c:76:8a:82:25:21

所占用的资源为 2*1 + 6*5 = 32条acl资源。

总的占用资源把步骤1、步骤2和步骤3加起来就是总的资源占用。

总的占用资源把步骤1、步骤2和步骤3加起来就是总的资源占用。这个不影响业务，默认是硬Zone，硬件ACL实现，超出后硬件规格后，切软Zone，对业务无影响，只是实现方式的变化。