R系列路由器ATM E3 模块应用案例

ATM E3 模块应用案例

一、基本信息

某公司网络拓扑如下图所示。

二、网络规划

中心R3640E使用一块ATM E3卡接入电信ATM网，各县一台C1720接入本地帧中继网。

三、主要配置

R3640E配置：

#

interface Atm3/0

 frame-format g832-adm

 pvc max-number 100

#

interface Atm3/0.1

pvc mengzi 0/92

map ip 10.160.18.6 255.255.255.252 broadcast

description To MengZi

ip address 10.160.18.5 255.255.255.252

C1720配置：

interface Serial0.3 point-to-point

 description Frame-relay to Honghe

 backup delay 10 10

 backup interface Serial1

 ip address 10.160.18.6 255.255.255.252

 frame-relay interface-dlci 16

ATM E3接口参数：

<Huawei-HongH>dis int atm

Atm3/0 current state :UP  

Line protocol current state :UP

Description :  Atm3/0 Interface

The Maximum Transmit Unit is 1500

Internet protocol processing : disabled

AAL enabled: AAL5, Maximum VCs: 100

Current VCs: 6 (0 on main interface)

Physical layer is ATM over E3

Scramble enabled, G.832 ADM frame format, clock slave, loopback not set

Atm3/0.1 current state :UP  

Line protocol current state :UP

Description : To MengZi

The Maximum Transmit Unit is 1500

Internet Address is 10.160.18.5/30

Sub-interface type: multi-point, VCs on sub-interface: 1

Atm link check function: disable

Physical layer is ATM over E3

Scramble enabled, G.832 ADM frame format, clock slave, loopback not set

[Huawei-HongH]ping 10.160.18.14

  PING 10.160.18.14: 56  data bytes, press CTRL_C to break

    Reply from 10.160.18.14: bytes=56 Sequence=1 ttl=255 time=14 ms

    Reply from 10.160.18.14: bytes=56 Sequence=2 ttl=255 time=14 ms

    Reply from 10.160.18.14: bytes=56 Sequence=3 ttl=255 time=14 ms

    Reply from 10.160.18.14: bytes=56 Sequence=4 ttl=255 time=15 ms

    Reply from 10.160.18.14: bytes=56 Sequence=5 ttl=255 time=14 ms

    0.00% packet loss

    round-trip min/avg/max = 14/14/15 ms

四、备注

ATM网与FR网在电信端有专有互联设备，终端只要配置好本段即可。

电信网管可以看到终端ATM状态(up/down)，终端ATM E3参数要与电信端设备参数相匹配。